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3x^2-60x-24000=0
a = 3; b = -60; c = -24000;
Δ = b2-4ac
Δ = -602-4·3·(-24000)
Δ = 291600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{291600}=540$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-540}{2*3}=\frac{-480}{6} =-80 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+540}{2*3}=\frac{600}{6} =100 $
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